Find the 5th term from the end of an AP:7,10,13,......,154
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the general formula of A. P. = a + ( n-1 ) d
a is first term = 7
n is the any term. = 5
d is difference bet. term. = 3
according to formula of A. P.
a+(n-1) d = 7 + (5-1) 3 = 7 + (4) 3 = 7 + 12 = 19
a is first term = 7
n is the any term. = 5
d is difference bet. term. = 3
according to formula of A. P.
a+(n-1) d = 7 + (5-1) 3 = 7 + (4) 3 = 7 + 12 = 19
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