Question

find the 5th term from the end of the G.P. 3, 6, 12, 24, ...,12288 is?

Answer 1

you can see your answer

Answer 2

768

Step-by-step explanation:

The G.P. is given by 3, 6, 12, 24, ........, 12288.

Now, the first term (a) of the G.P. is 3 and the common ratio (r) is 2.

Let us assume that the nth term is 12288.

So, $ar^{n - 1} = 12288$

⇒ $3(2)^{n - 1} = 12288$

⇒ $2^{n - 1} = 2^{12}$

⇒ n - 1 = 12

⇒ n = 13

Therefore, the 13th term of the G.P. is 12288.

We need to determine the 5th term of the G.P. from its end i.e. the 9th term from the start.

So, the 9th term of the G.P. is $3(2)^{9 - 1} = 768$. (Answer)