Question

Find the 5th term of an AP: 2p+1/p , 2p−1/ p , 2p−3/p​

Answer 1

Answer:

If the numbers a,b and c are in AP, then

b-a=c-b

⇒2b=a+c

The given three numbers (2p-1),(3p+1) and 11 are in AP.

Then,

2(3p+1)=(2p−1)+11

⇒6p+2=2p−1+11

⇒6p+2=2p+10

⇒6p−2p=10−2

⇒4p=8

⇒p=8/4

⇒p=2

So, the value of p is 2.

Then, the given numbers be

2×2−1,3×2+1,11

4−1,6+1,11

3,7,11

Explanation:

Answer 2

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If the numbers a,b and c are in AP, then

b-a=c-b

⇒2b=a+c

The given three numbers (2p-1),(3p+1) and 11 are in AP.

Then,

2(3p+1)=(2p−1)+11

⇒6p+2=2p−1+11

⇒6p+2=2p+10

⇒6p−2p=10−2

⇒4p=8

⇒p=8/4

⇒p=2

So, the value of p is 2.

Then, the given numbers be

2×2−1,3×2+1,11

4−1,6+1,11

3,7,11

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