Question

Find the 5th term of G.P 4,12,36.....

Answer 1

Step-by-step explanation:

a=4

r=3

$t = {ar}^{(n - 1)} \\ t = 81 \times 4 \\ t = 324$

Answer 2

The $n^{th}$ term of GP is "324".

Step-by-step explanation:

The given sequence

4, 12, 36, ... are in GP.

Here, first term(a) = 4, common ratio(r) = $\dfrac{second term}{first term}$ = $\dfrac{12}{4}$ = 3

We know that,

$n^{th}$ term of GP = a$r^{n - 1}$

∴ $5^{th}$ term of GP = 4 × $3^{5 - 1}$

= 4 × $3^{4$

= 4 × 81

= 324

Hence, the $n^{th}$ term of GP is 324.