Question

Find the 6 "term of the A.P. 17, 14, 11, ..​

Answer 1

Answer:

$a = 17 \: \: \: \: d = 14 - 17 = - 3 \\ an = a + (n - 1)d \\ an = 17 + (6 - 1) - 3 \\ 17 + 5 \times( - 3) \\ = 17 - 15 \\ = 2$

Answer 2

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Given:-

AP= 17,14,11..-4

So, now we need the 6th term from last. SO, by reversing the AP, we get;

AP = -40,-37,-31......14,17

Now, Given;

d=3

a1=-40

n=6

Therefore a6= a+(n-1)d

=a

6

=−40+(6−1)3

=a

6

=−40+5∗3

=a

6

=−40+15

=a

6

=−25

So the 6th term is−25

HOPE THIS WILL HELPS U...