find the 60th term of ap 8,10,12if it has a total of 60 terms and hence find its last 10 terms.
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a=8 d=2
a60=a+(60-1)d
=8+59×2
=8+118
a60=126
reverse AP:126,126-2,126-4....
126,124,122,120,118,116
s10(from last)=10/2{2a'+(10-1)d'}
=5{2×126+9×(-2)}
=5{252-18}
=234×5
=1170
a60=a+(60-1)d
=8+59×2
=8+118
a60=126
reverse AP:126,126-2,126-4....
126,124,122,120,118,116
s10(from last)=10/2{2a'+(10-1)d'}
=5{2×126+9×(-2)}
=5{252-18}
=234×5
=1170
ansss:
hope it helps....☺
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