Find the 66th term of the arithmetic sequence with first term 1/2 and common difference -1/3
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EXPLANATION.
First term of an a.p. = 1/2.
Common difference = - 1/3.
As we know that,
General term of an a.p.
⇒ Tₙ = a + (n - 1)d.
To find : 66th term of an a.p.
⇒ T₆₆ = a + (66 - 1)d.
⇒ T₆₆ = a + 65d.
Put the values in the equation, we get.
⇒ T₆₆ = (1/2) + 65(-1/3).
⇒ T₆₆ = 1/2 - 65/3.
⇒ T₆₆ = (3 - 130)/6.
⇒ T₆₆ = - 127/6.
66th term of an a.p. : T₆₆ = -127/6.
MORE INFORMATION.
Supposition of terms in an a.p.
(1) Three terms as : a - d, a, a + d.
(2) Four terms as : a - 3d, a - d, a + d, a + 3d.
(3) Five terms as : a - 2d, a - d, a, a + d, a + 2d.
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