Find the 68th term of the arithmetic sequence -19, -33, -47
Answers
Answered by
0
a=-19
d= -33-(-19)=-14
n=68
68th term= a+(n-1)d
= 19+(67)(-14)
=-919
Answered by
2
Answer:
-19+67*-14, using a+(n-1)d
-957
Step-by-step explanation:
Similar questions