find the 6th term and the nth term of the sequence 3/2,3/4,3/8...
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A.P = 3/2, 3/4 , 3/8
d = 3/4 - 3/2 = - 3/4
a = 3/2
6th term = a + 5d
= 3/2 + 5 × -3/4
= 3/2 - 15/4
= 6 - 15 / 4
= -9/4
nth term = a + (n-1)d
=> an = 3/2 -3/4 n + 3/4
=> an = 3/2 + 3/4 - 3/4n
=> an = 9/4 - 3/4n
=> an = 3/4 ( 3 - n )
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Answer:
the answer is 3by 64 and 3by 2n
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