Find the 6th term from end of the AP 17, 14, 11,... ,-40
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Given,
AP... 17,14,11..-40
So, now we need the 6th term from last. SO, by reversing the AP, we get;
AP = -40,-37,-31......14,17
Now, Given;
d=3
a1=-40
n=6
Therefore a6= a+(n-1)d=a6
−40+(6−1)3=a6
−40+5∗3=a6
−40+15=a6
=−25
So the 6th term is−25
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