Question

find the 6th term from the end of ap 17,14,11.....which has 30terms​

Answer 1

Given

17, 14, 11....are in AP

Total number of terms = 30

FORMULA USED

aₙ = a + (n-1)d

aₙ = The last term

a = The first term

n = number of terms

d = Common difference

The 6th term from the end is the 24th term

$\implies a + 23 d$

Here a = 17 and d = -3

Substituting, we get,

$\implies 17-69\\\implies -52$

                                                 

Answer 2

$\rm \: AP= \: 17,14,11,........$
$\rm \: Number \: of \: terms = 30$
$\rm \bf Common \: difference= 14-17=-3$
$\rm {6}^{th} \: term \: from \: the \: end \: = {24}^{th} \: term$
$\: \: \: \: \: \: \: \: \: \: \: \: \bf \boxed{ \rm \bf \: x_{n} = a + (n - 1)d}$
$\rm {24}^{th} \: term = 17 + (24 - 1) - 3 \\ \rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 17 - 69 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = - 52$
$\bf \huge \: Hope \: it \: helps \: u$