find the 6th term from the end of the AP 17, 14 ,11,...........,40
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GIVEN : A.P = 17, 14,11,.....,40.
WE HAVE TO FIND 6TH TERM FROM END SO WE'LL REVERSE THE AP
REVERSE FORM OF AP = 40,....,11,14,17
d = 14 - 17 = -3 , a = 40
tn = a + (n-1) d
t6 = 40 + ( 6 - 1 ) × ( -3)
t6 = 40 + 5 × ( -3 )
t6 = 40 + ( -15 )
t6 = 40 - 15
t6 = 25
THE 6TH TERM OF AN AP FROM THE END US 25.
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