Question

find the 6th term in the expansion of
[tex](x - 3/x²)¹
​

Answer 1

Explanation:

The given term is (x3−x21)10.

The general term of expansion of (a+b)n is,

Tr+1=nCran−rbr

The sixth term of the expansion of (x3−x21)10 is,

T5+1=10C5(x3)10−5(−x21)5

=−5!(10−5)!10!(x3)5((x2)51)

=−5!5!10!(x15)(x101)