find the 6th term of (2+x)^10
Answers
Answered by
1
Answer:Explanation:
We know that, the General
(
r
+
1
)
t
h
Term, i.e.,
T
r
+
1
,
in
the expansion of
(
a
+
b
)
n
is given by,
T
r
+
1
=
n
C
r
a
n
−
r
b
r
,
r
=
0
,
1
,
2
,
...
,
n
.
We have,
a
=
x
,
b
=
−
1
2
,
n
=
10
,
&
,
since
T
6
is required,
r
=
5
.
Accordingly,
T
5
+
1
=
10
C
5
x
10
−
5
(
−
1
2
)
5
,
=
(
10
)
(
9
)
(
8
)
(
7
)
(
6
)
(
1
)
(
2
)
(
3
)
(
4
)
(
5
)
x
5
(
−
1
2
5
)
,
⇒
T
6
=
−
63
8
x
5
.
Step-by-step explanation:
Similar questions