Question

Find the 6th term of a GP whose 4th term is 81 and the common ratio is 3​

Answer 1

Answer:

6th term is 729

Step-by-step explanation:

$4^{th} term= ar^{3}= 81\\a= 81/r^{3}\\a= 81/27 , (r=3)\\a=3\\\\\\6^{th} term = ar^{5} \\=3(3)^{5}\\ =729$

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Answer 2

Answer:

The second term = ar = 81/2 ...(1)

the fifth term = ar^4 = 1/6 ....(2)

devide (2) by (1)

r^3 = (1/6)(81/2) = (1*2/6*81) = ( 1/234) or

r = 1/6.240251469 = 0.160249952 and

a = 252.7301845 and the common ratio is r = 0.160249952.

Step-by-step explanation:

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