Question

Find the 6th term of an AP. 3. 5. 7​

Answer 1

common differfence = 5-3=2

An= a1+(n-1)d

=5+(6-1)2

=5+5*2

=5+10

=15

Answer 2

Answer:

${ \large{ \underline { \sf{Given}}}}$

$\: \: \: \: \: \: \: \: { \sf{❍ \: The \: Terms \: of \: AP \: are \: 3,5,7}}$

${ \large{ \underline{ \sf{To \: Find}}}}$

$\: \: \: \: \: \: \: \: { \sf{❍ \: 6th \: Term \: of \: AP??}}$

${ \large{ \underline{ \sf{Solution}}}}$

• First We have to use nth term formula, thus we can find 6th term of AP, So for finding this we should have a, d values. Let's start our solution.

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${\underline{\sf{From\: Question,}}}$

• First term (a) = 3

• Common difference (d) = 2

• n = 6

${\underline{\sf{Formula,}}}$

• ${ \boxed{ \sf{ a_{n} = a + (n - 1)d}}}$

${\underline{\sf{By \: Substituting,}}}$

${ \dashrightarrow{ \sf{ a_{6} = 3 + (6 - 1)2}}} \\ \\ \\ { \dashrightarrow{ \sf{ a_{6} = 3 + (5)2}}} \\ \\ \\ { \dashrightarrow{ \sf{ a_{6} = 3 + 10 }}} \\ \\ \\ { \dashrightarrow{ \sf{ a_{6} =13 }}} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: { \boxed{ \boxed{ \sf {\therefore{ \pink{6th \: Term \: of \: AP \: is \: 13}}}}}}$

Explanation:

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