Question

find the 6th term of the A.P 17,11,14​

Answer 1

AP IS 11,17,14

T1 = 11

T2 = 14

T3 = 17

T2- T1 = d T3 -T2 =d

14 - 11 17 - 14.

= 3. =3

AS PER FORMULA,

D=3

A=T1 =11

Tn=?

n= 6

Tn=a+ (n-1) d

Tn = 11+ (6-1)3

=11 + 5 X 3

= 11 + 15

= 26

THEREFORE THE SIXTH TERM OF AN AP 11,14,17 IS 26

FOR CROSS CHECKING YOU CAN ADD UP AND SEE EG:- T3=17

so, T3- T4 = d -----> T4= T3+D

17+3+3+3 = 26

THE ABOVE STEP OF CROSS CHECKING IS OPTIONAL ITS EXTRA DO NOT WRITE IN EXAM!!!

HOPE IT HELPS IF YES PLS MARK ME BRAINLIEST...