find the 7 term from the end of arithmatic progression 7, 10,13, ------184
Answers
Answered by
2
a=7
d=3
Tn=184
T7=a+6d
T7=7+6(3)
T7=7+18
T7=25
d=3
Tn=184
T7=a+6d
T7=7+6(3)
T7=7+18
T7=25
Answered by
1
166 is the ans we're
Attachments:
Similar questions