find the 7th term form the end of the arithmetic progression 7,10,13.....184
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Answered by
12
Hey mate!
To find the 7th term from the end, the AP will become,
184,...,13,10,7
Here,
a=184; d=-3; n=7
We know that,
an = a+(n-1)d
Substituting the values,
a7 = 184+(7-1)-3
=> 184+(6)-3
=> 184-18
=> 166.
Therefore, the 7th term from the end of the AP is 166.
Hope it helps :)
To find the 7th term from the end, the AP will become,
184,...,13,10,7
Here,
a=184; d=-3; n=7
We know that,
an = a+(n-1)d
Substituting the values,
a7 = 184+(7-1)-3
=> 184+(6)-3
=> 184-18
=> 166.
Therefore, the 7th term from the end of the AP is 166.
Hope it helps :)
Answered by
3
Answer: 166
Refer the attachment for the steps
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