Question

Find the 7th term from the end of AP 11,17,23,29,.......605.

Answer 1

if reversed
605,....,29,23,17,11
a = 605
d = -6

7th term
n=7
tn=a+(n-1)×d
t7=605+(7-1)×-6
=605-36
=569

Hope it helps.....