Question

Find the 7th term from the end of AP 17,21,25,-----------93

Answer 1

Explanation:

a=17

d=?

a2-a1=a3-a2

21-17=25-21

4=4

therefore d=4

7th term of ap = a+6d

=17+6×4

=17+24

=41

hence 41 is the 7th term

Answer 2

Given:

An AP.

17, 21, 25,-----------93

To find:

The 7th term from the end of AP.

Solution:

The 7th term from the end of AP is 69.

To answer this question, we will follow the following steps:

As we know that the nth term of an A.P. is given by

${n}^{th} \: term = a + (n - 1)d$

Now,

As given, we have an A.P.

17, 21, 25,----------- 93

After reversing the above A.P., we have

93, ---------25, 21, 17

Now,

We have,

First-term = 93

Common difference = 21 - 25 = -4

So,

The 7th term of the A.P. is

$= 93 + (7 - 1) \times - 4$

$= 93 + (6) \times - 4$

$= 93 - 24$

$= 69$

Hence, the 7th term from the end of AP is 69.