Find the 7th term from the end of the AP : , 10, 13, …, 184.
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EXPLANATION.
- GIVEN
sequence of an Ap = 10,13,16 ............184
To find seventh term from end of an Ap.
Let the new Ap will be written as
=> 184 , 181 , 178 , ......10
First term = a = 184
Common difference = d = b - a = 181 - 184 = -3
Formula of Nth term of an Ap.
=> An = a + ( n - 1 ) d
=> T7 = a + 6d
=> 184 + 6 ( -3)
=> 184 - 18
=> 166
Therefore,
7th term of an Ap = 166
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