find the 7th term from the end of the AP 7,10,13...184.
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Answered by
7
a = 7
d =a2-a1 = 10-7=3
l = last term = n th term = 184
7 th term=a7=a+6d=7+6(3) = 7 + 18 =25
The 7th term of the given Ap from starting is 25
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d =a2-a1 = 10-7=3
l = last term = n th term = 184
7 th term=a7=a+6d=7+6(3) = 7 + 18 =25
The 7th term of the given Ap from starting is 25
Hope it will help you
Plz mark it as brainliest
KhushiG:
plz mark it as brainliest answer
this answer is wrong the correct answer is 1/66
This answer is wrong!!. It was asked 7th term from the last.. My answer is below this. That is correct.
Answered by
5
Given,
A.P. is 7,10,13,......,184.
a = 7.
d = 10-7= 3.
an= 184.
We know,
an= a+(n-1)d.
Proof,
184= 7+(n-1)3
177=(n-1)3
59=(n-1)
n=60.
Therefore, total no. of terms in the A.P. is 60.
Therefore 7th term from the end is 53 i.e 60-7=53.
Therefore,
an= a+(n-1)d
a53 = 7+(53-1)3
= 7+52*3
= 7+156
a53 = 163.
Therefore the 7th term from the end of the A.P. is 163.
A.P. is 7,10,13,......,184.
a = 7.
d = 10-7= 3.
an= 184.
We know,
an= a+(n-1)d.
Proof,
184= 7+(n-1)3
177=(n-1)3
59=(n-1)
n=60.
Therefore, total no. of terms in the A.P. is 60.
Therefore 7th term from the end is 53 i.e 60-7=53.
Therefore,
an= a+(n-1)d
a53 = 7+(53-1)3
= 7+52*3
= 7+156
a53 = 163.
Therefore the 7th term from the end of the A.P. is 163.
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