Question

find the 7th term from the end of the arithmetic progression 7 ,10 13,........184

Answer 1

a=7
d=10-7
=3
l=184


a7=L-(n-1)d
a7=184-(7-1)3
a7=184-18
a7=166

so..7th term from last is 166.

Hope it helps uh out!!!

Answer 2

a = 7
d= a2-a1
d= 10 -7 = 3
l = 184
therefore the a7 term is
a = 184- (n-1) 3. ...... because nth term from end is = l-(n-1)d
=184 + 6( 3)
= 184 - 18
= 166