Question

find the 7th term of 4 x by 5 minus 5 by 2 X whole power 9 when expanded in ascending power of x​

Answer 1

Answer:

Solution :

T7=T6+1=9C6(4x5)9−6(−52x)6

9!(6!3!)⋅(4)353⋅x3⋅(−5)626⋅1x6

84⋅(53)x3

84⋅125x3

10500x3.

Step-by-step explanation:

Solution :

T7=T6+1=9C6(4x5)9−6(−52x)6

9!(6!3!)⋅(4)353⋅x3⋅(−5)626⋅1x6

84⋅(53)x3

84⋅125x3

10500x3.

hope this helps