find the 7th term of an AP :a,3a,5a.
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Answered by
1
Difference of each term is 5a-3a=2a
So ap is a. 3a.5a.7a.9a.11a.13a.15a
Hope it helps u dear.....
Answered by
0
Answer:
given:
A.P= a, 3a, 5a...
d(common difference)= 3a-a = 2a
n(nth term)=7
A(first term)=a
as we know that:
A(n)=A+(n-1)d
ATQ:
A(7)=a+(7-1)2a
A(7)=a+12a
A(7)=13a
hence, the 7th term of the given A.P is 13a.
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