Find the 7th term of the sequence 2, 9, 28, 65, 126, 217
Answers
Answer:
This is a number series of sum of a cube and 1
2 = 1*1*1 +1
9= 2*2*2+2
28 = 3*3*3+1
65= 4*4*4+1
126=5*5*5+1
217=6*6*6+1
344= 7*7*7+1
So next number will be
8*8*8+1 =513
Given:
A sequence: 2, 9, 28, 65, 126, 217
To find:
The 7th term of the sequence
Solution:
We can find the solution by following the given steps-
We know that the sequence is based on a certain pattern that has been followed throughout.
The terms are formed as the cube of the first six natural numbers+1.
The first term is 2 which is formed by adding the cube of the first natural number and one.
2= 1³+1 =1+1
Similarly, all the other terms are-
9=2³+1 =8+1
28=3³+1= 27+1
65=4³+1=64+1
126=5³+1=125+1
217=6³+1=216+1
So, the 7th term would be the cube of 7 plus 1.
The 7th term= 7³+1
=343+1
=344
Therefore, the 7th term of the sequence is 344.