Question

Find the 7th term of the sequence below. Tn= 3n^2+5n−2

Answer 1

Answer:

T 5=3(5)-7 = 15–7 =8

Another method

Tn = 3n - 7T 1 = 3(1)-7 = -4T 2 = 3(2) -7= -1d= t 2 - t 1 = -1 -(-4)=3a = -4 d=3Tn = a + (n-1)d =T 5 = a + (5–1)d = a +4 d = -4 +4(3)= 8

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Answer 2

Answer:

T7 = 180

Step-by-step explanation:

Putting value 7 in place of n and using BODMAS