Question

find the 8 terms of the AP whose first term is -2 and common difference is 3​

Answer 1

Answer:

The AP is -2, 1, 4, 7, 10, 13, 16, 19...

8th term is 19

8th term = first term + 7(common distance)

a8 = a + (n-1)d

= -2 + (8-1)3

= -2+ 21

a8 = 19

Answer 2

Answer:

The 8 terms of AP are:
1st term= -2
2nd term= 1
3rd term= 4
4th term= 7
5th term= 10
6th term= 13
7th term= 16
8th term= 19

Step-by-step explanation:

Arithmetic progression:
Arithmetic Progression (AP) is a sequence or series of numbers in order, in which the difference between any two consecutive numbers is always constant, known as common difference (d).

Formula to calculate $n^{th}$$term$ of an AP
= $a+ (n-1)d$
where,
$a$ is the first term of the AP
$n$ is the number of terms in the series
$d$ is the common difference

Now, according to the question

$a=$ -2
$d=$ 3

∴ Using the formula to find out the $n^{th}$ $term$:

2nd term= -2+(2-1)×3
= -2+3
= 1

3rd term= -2+(3-1)×3
= -2+6
= 4

4th term= -2+(4-1)×3
= -2+9
= 7

5th term= -2+(5-1)×3
= -2+12
= 10

6th term= -2+(6-1)×3
= -2+15
= 13

7th term= -2+(7-1)×3
= -2+18
= 16

8th term= -2+(8-1)×3
= -2+21
= 19

∴ The first 8 terms of the AP are:
= -2, 1, 4, 7, 10, 13, 16, 19