Math, asked by birbikram3039, 1 year ago

Find the 8 th term from the end of AP 7,10,13.....184

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Answered by Dchetry1
11
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Answered by amirgraveiens
3

Hence the 8 th term from the end of AP 7,10,13.....184 is 163.

Step-by-step explanation:

Given:

The given A.P is 7, 10, 13,....,184

So the common difference is, second term - first term

= (10−7) = (13−10) = 3.

Now, if we reverse the sequence of A.P then it becomes 184, 181, 178,...,13, 10, 7.

Therefore, from the end the common difference of the A.P is,

d= (181−184) =−3                     [1]

Now, nth term=a+(n−1)d where a = first term of the A.P.

Hence, 8th term from the end of given of the A.P

= 8th term from the beginning of the A.P 184, 181, 178,....,13, 10, 7

=184+(8−1)(−3)                                           [ 8th term n=8, d = -3 from (1) ]

=184−21

=163

Hence the 8 th term from the end of AP 7,10,13.....184 is 163.

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