Find the 8 th term from the end of AP 7,10,13.....184
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Hence the 8 th term from the end of AP 7,10,13.....184 is 163.
Step-by-step explanation:
Given:
The given A.P is 7, 10, 13,....,184
So the common difference is, second term - first term
= (10−7) = (13−10) = 3.
Now, if we reverse the sequence of A.P then it becomes 184, 181, 178,...,13, 10, 7.
Therefore, from the end the common difference of the A.P is,
d= (181−184) =−3 [1]
Now, nth term=a+(n−1)d where a = first term of the A.P.
Hence, 8th term from the end of given of the A.P
= 8th term from the beginning of the A.P 184, 181, 178,....,13, 10, 7
=184+(8−1)(−3) [ 8th term n=8, d = -3 from (1) ]
=184−21
=163
Hence the 8 th term from the end of AP 7,10,13.....184 is 163.
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