Question

find the 8term from the end of the sequence, 2,6,18........39366​

Answer 1

Answer:

768

Step-by-step explanation:

The G.P. is given by 3, 6, 12, 24, ........, 12288.

Now, the first term (a) of the G.P. is 3 and the common ratio (r) is 2.

Let us assume that the nth term is 12288.

So, ar^{n - 1} = 12288ar

n−1

=12288

⇒ 3(2)^{n - 1} = 122883(2)

n−1

=12288

⇒ 2^{n - 1} = 2^{12}2

n−1

=2

12

⇒ n - 1 = 12

⇒ n = 13

Therefore, the 13th term of the G.P. i