Question

Find the 8th term from the end of AP 17, 14, 11, _____, -40

Answer 1

AP:8,10,12,...126

AP:8,10,12,...126 a=8,d=2,an=126

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1)

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginning

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a 51

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a 51

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a 51 =a+(51−1)d

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a 51 =a+(51−1)d=8+50×2

AP:8,10,12,...126 a=8,d=2,an=126 Now an=a+(n−1)d 126=8+(n−1)2 ⇒118=(n−1)2 ⇒59=n−1 ⇒n=60 Now 10 th term from last is (60−10+1) th term=51 th term from beginningSo, a 51 =a+(51−1)d=8+50×2=8+100=108