Question

Find the 8th term from the end of the GP 3 , 6 , 12 , 24 ,..., 6144.

Answer 1

Answer:

Solution :

Given G.P. is 3,6,12,24,....,6144.

Here a = 3, r = 6 / 3 = 2, and l = 6144.

∴ 8th term from the end = 1 / r^(8 - 1)

= 6144 / 2^7 = 6144 / 128 = 48 [ ∵ nth term from

the end = 1 / r ^ n - 1 ]

Hence, the 8th term from the end is 48.

Step-by-step explanation:

@GENIUS

Answer 2

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$\huge\bf{Answer:-}$

$S_{s} = 765$

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$\huge\bf{Solution:-}$

Here,

$a = 3 \\ r = 2 > 1 \\ n = 8$

Using Formula,

$</u><u>s</u><u>_{</u><u>s</u><u>} = \frac{a( {r}^{n } - 1)}{ (r - 1)}$

We get,

$S_{s} = \frac{3 \times ( {2}^{8} - 1) }{(2 - 1)} \\ = 3 \times (256 - 1) \\ = 3 \times 255 \\ = 765$

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