Math, asked by waseemkayani5084, 1 year ago

Find the 8th term in series? 2, 2, 12, 12, 30, 30, - - - - -

Answers

Answered by CoruscatingGarçon
2

1^1+1=2

2^2-2=2

3^2+3=12

4^2-4=12

5^2+5=30

6^2-6=30

so next two

7th=(7^2+7)=56 & 8th=(8^2-8)=56

ans 56

Answered by throwdolbeau
3

Answer:

The 8th term will be 56

Step-by-step explanation:

First term is obtained by :

1² + 1 = 2  

Second term is obtained by :

2² - 2 = 2

Third term is obtained by :

3² + 3 = 12  

Fourth term is obtained by :

4² - 4 = 12

Fifth term is obtained by :

5² + 5 = 30

Sixth term is obtained by :

6² - 6 = 30

Similarly, Seventh term is obtained by :

7² + 7 = 56

And, The required Eighth term will be :

8² - 8 = 56  

Hence, The 8th term will be 56

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