Find the 8th term in the expansion of (√2+√3) According to binomial theorem.
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Answer:
We have, (2a−3b)
n
⇒
n
C
6
(2a)
n−6
(−3b)
6
=
n
C
7
(2a)
n−7
(−3b)
7
⇒
n
C
6
(2a)=
n
C
7
(−3b)
⇒
3b
2a
=−
n
C
6
n
C
7
⇒
3b
2a
=−
(n−6)!6!
n!
(n−7)!7!
n!
⇒
3b
2a
=−
7
n−6
⇒
3b
2a
=
7
6−n
On applying componendo and diviend, we get
2a−3b
2a+3b
=
6−n−7
6−n+7
=
−(n+1)
13−n
=[
n+1
n−13
]
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