Question

find the 8th term of a geometric sequence for which a1 = -3,r = -2​

Answer 1

Step-by-step explanation:

use the formula a=a+(n-1)d

it will help u

Answer 2

Given :

In a geometric sequence,

a= -3

r = -2

To find :

8th term of sequence

solution :

we know,

$T_n=a\times {r}^{n-1}\\\\T_8=(-3)\times {(-2)}^{7}\\\\T_8=(-3)\times(-128)\\\\T_8=384\\\\\underline{\boxed{\sf{ T_8=384}}}$