find the 8th term of an ap 1,3,5,7.....
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Answered by
10
first term a = 1
common difference = 3 - 1 = 2
T8 = a + ( n - 1)d
T8 = 1 + (8-1)2
T8 = 1 + 7*2
T8 = 1 + 14
T8 = 15
common difference = 3 - 1 = 2
T8 = a + ( n - 1)d
T8 = 1 + (8-1)2
T8 = 1 + 7*2
T8 = 1 + 14
T8 = 15
Answered by
7
Hey! Here is ur answer...
A/Q ;
first term = a = 1
& their common difference = d = 2
So, applying formula of nth term of AP ;
● [ Tn = a + (n - 1) d ]
=> T(8) = a + (8 - 1) d
=> T(8) = a + 7d
=> T(8) = 1 + 7×2
=> T(8) = 1 + 14 = 15
Hence, 8th term of given AP is 15.
Hope this helps u...Plz mark it as brainliest...☺
A/Q ;
first term = a = 1
& their common difference = d = 2
So, applying formula of nth term of AP ;
● [ Tn = a + (n - 1) d ]
=> T(8) = a + (8 - 1) d
=> T(8) = a + 7d
=> T(8) = 1 + 7×2
=> T(8) = 1 + 14 = 15
Hence, 8th term of given AP is 15.
Hope this helps u...Plz mark it as brainliest...☺
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