Question

find the 8th term of an exponential sequence whose first term is 3 whose common ratio is 2​

Answer 1

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Answer 2

SOLUTION

TO DETERMINE

The 8th term of an exponential sequence whose first term is 3 and common ratio is 2

FORMULA TO BE IMPLEMENTED

If in an exponential sequence first term = a and common ratio = r then

$\sf{nth \: term \: = a \times {r}^{n - 1} }$

EVALUATION

Here it is given that in an exponential sequence first term is 3 and common ratio is 2

So 8 th term of the sequence

$\sf{ = 3 \times {2}^{8 - 1} }$

$\sf{ = 3 \times {2}^{7} }$

$\sf{ = 3 \times 128}$

$\sf{ = 384}$

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