Question

find the 8th term of AP root 3, root 12 root27, root 75​

Answer 1

Answer:8root3

Explanation:an=a+(n-1)d

a8=root3+(8-1)(root3)

a8=root3+7root3

a8=8root3

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Answer 2

AP- Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

Given: $\sqrt{3}$, $\sqrt{12\\}$, $\sqrt{27}$, $\sqrt{75}$

$\sqrt{3}$,$\sqrt{3X4}$,$\sqrt{3X9}$,$\sqrt{3X16}$,$\sqrt{3X25}$.... and so on

=> Here $\sqrt{3},2\sqrt{3} ,3\sqrt{3}$ all are in AP,

where a=$\sqrt{3}$ and d=$2\sqrt{3}-\sqrt{3}=\sqrt{3}$

therefore, the 8th term is a+8d = $\sqrt{3}+8\sqrt{3} = 9\sqrt{3}$

$\sqrt{3X81}= \sqrt{243}$

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https://brainly.in/question/696747?msp_srt_exp=6

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