Question

Find the 8th term of the series 4,-8, 16, -32 ​

Answer 1

here's your

Answer:

$- 2 ^{2} = 4 \\ { - 2}^{3} = - 8 \\ { - 2}^{4} = 16 \\ { - 2}^{5 } = - 32 \\ { - 2}^{6} = 64 \\ - {2}^{7} = - 128 \\ - {2}^{8} = 256$

Requeste:

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Answer 2

$\huge\red{\boxed{ANSWER}}$

I THINK THAT YOUR QUESTION IS NOT IN AN A.P.

BUT IT CAN BE SOLVED LIKE I DID BELOW

4 , ( 4× -2 ) = -8 , (-8 × -2) = 16 , ( 16 × -2 ) = -32 , ( -32 × -2 ) = 64 , ( 64 × -2 ) = -128 , ( -128 × -2 ) = 256 , ( 256 × -2 ) = -512 , ( -512 × -2 ) = 1024 , ( 1024 × -2 ) = -2048.

ANSWER :-

1ST TERM = 4

2ND TERM = -8

3RD TERM = 16

4TH TERM = -32

5TH TERM = 64

6TH TERM = -128

7TH TERM = 256

8TH TERM = -512

9TH TERM = 1024

10TH TERM = -2048

$\huge\red{\boxed{\mathbb\purple{\fcolorbox{orange}{pink}{ANSWER}}}}$

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