Find the 93rd term of the arithmetic sequence -6 13 32
Answers
Answered by
0
A.P.---. -6,13,32
a=-6. d=13-(-6)=32-13=19
93rd term=a+(n-1)*d=(-6)+(93-1)19
=(-6)+1748=1742
It may be useful!
Answered by
0
Answer:
StepA.P.---. -6,13,32
a=-6. d=13-(-6)=32-13=19
93rd term=a+(n-1)*d=(-6)+(93-1)19
=(-6)+1748=1742-by-step explanation:
Similar questions