Math, asked by rd153888, 20 hours ago

Find the 93rd term of the arithmetic sequence -6 13 32

Answers

Answered by anjanasarkar200502
0

A.P.---. -6,13,32

a=-6. d=13-(-6)=32-13=19

93rd term=a+(n-1)*d=(-6)+(93-1)19

=(-6)+1748=1742

It may be useful!

Answered by hebbarsamarth
0

Answer:

StepA.P.---. -6,13,32

a=-6. d=13-(-6)=32-13=19

93rd term=a+(n-1)*d=(-6)+(93-1)19

=(-6)+1748=1742-by-step explanation:

Similar questions