Question

Find the 96th term of the arithmetic sequence -3, -14, -25, ...−3,−14,−25,

Answer 1

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• a = - 3
• d = - 14 + 3 = 11
• n = 96

$\tt{ an = a + ( n - 1 )d }$

• a 96 = - 3 + 95 × 11
• ___ - 3 + 1045
• ___ 1042

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Answer 2

Answer:

a96= a+95d --------(1)

here, a=-3

d=-25-(-14)

=-25+14=-11

sustituting the values in 1

so, 96th term = -3+95*-11

= -3-1045

=-1048

therefore 96th term of thisAP is-1048