Question

Find the 96th term of the arithmetic sequence -30, -32, -34, ...

Answer 1

Answer:

a = -30

d = -32 - (-30) = -2

n = 96

So, using A.P. formula-

Tn = a + (n-1) d

T96 = -30 + (96-1) -2

T96 = -30 + (95) -2

T96 = -30 - 190

T96 = -220

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Answer 2

Answer:

Here A.P. is -30, -32, -34........

Therefore,

a = -30

d = T2 - T1

= -32 - (- 30)

= -32 + 30

= -2

Tn = a + ( n- 1) d

T96= -30 + ( 96 -1) -2

= -30 + (95 -2)

= -30 -190

= -220

Therefore, 96 th term of A.P. is -220