Question

Find the √9801 by long division method​

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

Firstly we will make factors of 9801

Prime factorisation of 9801

$\begin{array}{r | l} 3 & 9801 \\ \cline{1-2} 3 & 3267 \\ \cline{1-2} 3 & 1089 \\ \cline{1-2} 3 & 363 \\ \cline{1-2} 11 & 121 \\ \cline{1-2} 11 & 11 \\ \cline{1-2} & 1 \end{array}$

Now,

$\small{\sf{→\sqrt{3 \times 3 \times 3 \times 3 \times 11 \times 11}}} \\ \\ \sf{→\sqrt{(3)^2 \times (3)^2 \times (11)^2}} \\ \\ \sf{→3 \times 3 \times 11} \\ \\ \sf{→99} \\ \\ \Large{\implies{\boxed{\boxed{\sf{99}}}}}$

$\rule{200}{2}$

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Answer 2

Answer:

id:=(773-7646-8564)

pwd:=(7)