Question

Find the 98th term of the arithmetic sequence 8, 24, 40, ...PLZ HELP FAST

Answer 1

Answer:

a=8

d=24-8

16

n=98

an=a+(n-1)d

an=4+(98-1)16

an=4+1552

an=1556

Answer 2

Answer: 1560

d=a 2​−a 1=(24)−(8)=16

an​=a1+(n−1)d

98th term

a98=8+(98−1)(16)

a98=8+(97)(16)

a{98}=1560