Find the 98th term of the arithmetic sequence 8, 24, 40, ...PLZ HELP FAST
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Answered by
0
Answer:
a=8
d=24-8
16
n=98
an=a+(n-1)d
an=4+(98-1)16
an=4+1552
an=1556
Answered by
0
Answer: 1560
d=a 2−a 1=(24)−(8)=16
an=a1+(n−1)d
98th term
a98=8+(98−1)(16)
a98=8+(97)(16)
a{98}=1560
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