Question

find the 99th term of the series 7.5, 9.5, 11.25,...... .

Answer 1

Here is your answer,

Let a be the first term of this AP.
And d be the common difference

a = 7.75
d = 2

a99 = a+98d

= 7.5+98x2

= 7.75+ 196

= 202.75

Therefore, the 99th term of the series is 202.75

HOPE IT HELPS YOU ^-^ !!

Answer 2

Here we goo...
The given series is in AP..

a(first term) =7.5

difference =2

t99=a+(n-1)*d;

t99=7.5+(99-1)*2

t99=7.5+98*2

t99=7.5+196

=203.5 ..answer..

Hope it helps (｡’▽’｡)♡