find the 9th and 15th term of the series 128,64,32,16
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Answer:
t₉ =
t₁₅ =
Step-by-step explanation:
Given GP , 128,64,32,16
=> a = 128
r = t₂ / t₁ = 64/128 = 1/2
n'th term of a G.P is given by tₙ =
=> t₉ = 128* = 128*
=
=
=> t₁₅ = 128* = 128*
=
=
=
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