Question

find the 9th term and 16th term of 3, 8, 13, 18............ ​

Answer 1

Step-by-step explanation:

the progression is in A.P condition

a = 3

d = 8-3 = 5

An = a+(n-1)d

9th term is

n = 9

A9 = 3+(9-1)5

A9 = 3+40

A9 = 43

16th term is

n = 16

A16 = 3+(16-1)5

A16 = 3+(15)5

A16 = 3+75

A16 = 78

9th term and 16th term are 43 , 78 respectively