Question

find the 9th term from the the end towards theend ( towards the first term) of the AP 5.9.13.185​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\sf\small{ \underline{\underline{ \pmb{Given:-}}}}$

AP 5,9,13,________185

• Therefore,
• a = 5
• d = 9-5 = 4
• an = 185

$\sf\small{ \underline{\underline{ \pmb{To \: find:-}}}}$

• the 9th term from the the end towards the end

$\sf\small{ \underline{\underline{ \pmb{ Solution:-}}}}$

$\sf \: a_n=a+(n−1)d$

$\sf \: ⟹5+(n−1)4=185$

$\sf \implies (n - 1)4 = 185 - 5$

$\sf \implies \: 4n - 4= 180$

$\sf \implies \: 4n = 180 + 4$

$\sf \implies \: 4n =184$

$\sf \implies \: n = \cancel \frac{184}{4}$

$\sf \implies n = 46$

So, 9th term from end will be the 38th term of this A.P

$\sf \implies \: a_{38} = a+37d$

$\sf \implies \: a_{38 }= 5+37 \times (4)$

$\sf \implies \: \: a_{38}=5+148$

$\sf \implies \: \: a_{38}=153$