Question

Find the 9th term in the expansion (2x-1)^9

Answer 1

Answer:

$9th \: term \:i s \: \: = \: \binom{10}{8} ( {2x})^{2} ( { - 1})^{8} \\ \\ = \binom{10}{8}( {2x})^{2} = 180 {x}^{2}$